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User:Hwangjy9/고등학교의 특별한 극한값

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< User:Hwangjy9

함수의 극한값

$lim_{x \to 0} \frac{\sin x}{x} = 1$

$lim_{x \to 0} \frac{\ln (1 + x)}{x} = 1$

$lim_{x \to 0} \frac{e^{x} - 1}{x} = 1$

증명

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